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b^2=13.824
We move all terms to the left:
b^2-(13.824)=0
We add all the numbers together, and all the variables
b^2-13.824=0
a = 1; b = 0; c = -13.824;
Δ = b2-4ac
Δ = 02-4·1·(-13.824)
Δ = 55.296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{55.296}}{2*1}=\frac{0-\sqrt{55.296}}{2} =-\frac{\sqrt{}}{2} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{55.296}}{2*1}=\frac{0+\sqrt{55.296}}{2} =\frac{\sqrt{}}{2} $
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